What is the chemical feed rate to obtain a 5 mg/L additive dose in a 5 million gallon per day wastewater flow?

What is the chemical feed rate to obtain a 5 mg/L additive dose in a 5 million gallon per day wastewater flow?

• A. 208 lbs/day
• B. 25 lbs/day
• C. 42 lbs/day
• D. 425 lbs/day

Answer: (A)

To determine the chemical feed rate required to achieve a specific dosage in wastewater treatment, you can use the following relationship: \[ \text{Feed Rate (lbs/day)} = \text{Concentration (mg/L)} \times \text{Flow Rate (GPD)} \times \text{Conversion Factor} \] In this case, you want to deliver a concentration of 5 mg/L into a flow of 5 million gallons per day. The conversion factor to go from mg/L to pounds per day is as follows: 1. Convert gallons per day to liters per day since 1 gallon is approximately 3.78541 liters: \[ 5,000,000 \text{ gallons/day} \times 3.78541 \text{ L/gallon} \approx 18,927,056 \text{ L/day} \] 2. Next, convert liters to milliliters. Since 1 liter equals 1000 milliliters: \[ 18,927,056 \text{ L/day} \times 1000 \text{ mL/L} = 18,927,056,000 \text{ mL/day} \] 3.

To determine the chemical feed rate required to achieve a specific dosage in wastewater treatment, you can use the following relationship:

[

\text{Feed Rate (lbs/day)} = \text{Concentration (mg/L)} \times \text{Flow Rate (GPD)} \times \text{Conversion Factor}

]

In this case, you want to deliver a concentration of 5 mg/L into a flow of 5 million gallons per day. The conversion factor to go from mg/L to pounds per day is as follows:

1. Convert gallons per day to liters per day since 1 gallon is approximately 3.78541 liters:

[

5,000,000 \text{ gallons/day} \times 3.78541 \text{ L/gallon} \approx 18,927,056 \text{ L/day}

]

2. Next, convert liters to milliliters. Since 1 liter equals 1000 milliliters:

[

18,927,056 \text{ L/day} \times 1000 \text{ mL/L} = 18,927,056,000 \text{ mL/day}

]