How would you calculate the volume of liquid in a tank with a diameter of 27 feet and a liquid level of 8 feet?

How would you calculate the volume of liquid in a tank with a diameter of 27 feet and a liquid level of 8 feet?

• A. 1268 gal
• B. 4578 gal
• C. 9156 gal
• D. 34240 gal

Answer: (C)

To determine the volume of liquid in a cylindrical tank, the formula used is: \[ \text{Volume} = \pi \times r^2 \times h \] where \( r \) is the radius of the tank and \( h \) is the height (or liquid level) in the tank. First, we need to find the radius from the given diameter. The diameter of the tank is 27 feet, so the radius (r) will be: \[ r = \frac{27}{2} = 13.5 \text{ feet} \] Next, the liquid level is given as 8 feet, so \( h = 8 \) feet. Now we can plug these values into the volume formula: \[ \text{Volume} = \pi \times (13.5)^2 \times 8 \] Calculating \( (13.5)^2 \): \[ (13.5)^2 = 182.25 \] Now, substituting this back into the volume equation: \[ \text{Volume} = \pi \times 182.25 \times 8 \] Calculating the volume: \[ \text{Volume} = \pi \times 1458

To determine the volume of liquid in a cylindrical tank, the formula used is:

[ \text{Volume} = \pi \times r^2 \times h ]

where ( r ) is the radius of the tank and ( h ) is the height (or liquid level) in the tank.

First, we need to find the radius from the given diameter. The diameter of the tank is 27 feet, so the radius (r) will be:

[ r = \frac{27}{2} = 13.5 \text{ feet} ]

Next, the liquid level is given as 8 feet, so ( h = 8 ) feet. Now we can plug these values into the volume formula:

[ \text{Volume} = \pi \times (13.5)^2 \times 8 ]

Calculating ( (13.5)^2 ):

[ (13.5)^2 = 182.25 ]

Now, substituting this back into the volume equation:

[ \text{Volume} = \pi \times 182.25 \times 8 ]

Calculating the volume:

[ \text{Volume} = \pi \times 1458